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Class 12
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5 Math Book
2:08
Continuity of Piecewise Functions — Determining Continuity
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Q) If tan^(−1) 𝑥=𝑦, then 𝑑𝑦/𝑑𝑥 is equal to #continuity_and_differentiability #maths #cbse
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Q) If sin^(−1) 𝑥=𝑦,then 𝑑𝑦/𝑑𝑥 is #maths #continuityanddifferentiabilityclass12 #class12 #cbse
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YouTube
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1:57
Q) If 𝑦=sin(𝑥+𝑦) and 𝑑𝑦/𝑑𝑥=0, then prove that 𝑦=±1.#class12maths
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YouTube
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1:09
Q) If 𝑓(𝑥)={(3𝑥−2, 0≤𝑥≤1 2𝑥^2+𝑎𝑥, 1≤𝑥≤2) is continuous for 𝑥∈(0,2), then a is equal to
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YouTube
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2:22
Find k so that 𝑓(𝑥)={((𝑥^2−2𝑥−3)/(𝑥+1), 𝑥≠−1 𝑘, 𝑥=−1) is continuous at x=−1.#cbse2027 #maths
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YouTube
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1:33
Q) Find the value of k, so that f(x)={ ((kcos x)/(𝜋−2x),if x≠𝜋/2 3, if x=𝜋/2) is contin
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1:49
Q) The derivative of cos^(−1)(2𝑥^2−1) with respect to cos^(−1)(𝑥) is
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1:21
Q) If e^y (x+1)=1, prove that dy/dx=−e^y #cbseclass12 #cbse2027 #maths # #cbsenotes
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2 months ago
YouTube
Shivang Maths Academy
2:59
Q) Show that the derivative of tan^(−1) (sec𝑥+tan𝑥),[−𝜋/2𝑥𝜋/2] with respect to x is equal to 1
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Q) If y=tan^(−1) [(√(1+x^2 )+√(1−x^2 ))/(√(1+x^2 )−√(1−x^2 ))], x^2≤1, then find dy/dx.
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YouTube
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Today, I had the privilege of sharing my story as part of Global Kinship Care Week with Kinship Care Ireland. It was a deeply meaningful day of reflection, recognition and celebration, honouring the grandparents, relatives and family friends who step forward to care for children when their parents are unable to do so. I am incredibly honoured to have been invited as one of today’s guest speakers and to use my own experience to help shine a light on the realities faced by kinship families. Kinshi
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Continuity test SUTT adalah pengujian untuk memastikan keterhubungan listrik (kontinuitas) penghantar SUTT dari satu titik ke titik lainnya tidak terputus, terutama setelah pekerjaan stringing, sagging, jointing, atau pemasangan jumper. Tujuannya antara lain: Memastikan konduktor terhubung secara kontinu dari ujung ke ujung. Memastikan jumper, joint, dan clamp terpasang dengan benar. Mendeteksi adanya konduktor putus atau sambungan yang tidak sempurna. Memastikan setiap fasa (R, S, T) sesuai dan
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